Final answer:
The magnitude of the electric field which is 12.0 N/C at 301 cm, will be 3.0 N/C 6.00 m away from the charge, as it follows the inverse-square law.
Step-by-step explanation:
The student's question asks about the electric field at different distances from a charged object. Specifically, they want to know the value of the electric field 6.00 m away, given that at 301 cm, the field's magnitude is 12.0 N/C. The electric field due to a point charge decreases with the square of the distance from the charge, according to the formula E = k * q / r^2, where E is the electric field, k is Coulomb's constant, q is the charge, and r is the distance from the charge.
By applying the inverse-square law, we know that if the distance is doubled, the electric field's magnitude will be reduced by a factor of 4 (since 2 squared is 4). To find the magnitude at 6.00 m (which is twice the distance of 3.01 m), we can simply divide the original magnitude by 4, leading to an answer of 3.0 N/C.