Final answer:
Using Charles's Law, we can calculate the volume of air exiting an evaporator after being cooled from 90°F to 70°F. By converting temperatures to Kelvin and applying the law's formula, we find that the volume decreases as the air cools.
Step-by-step explanation:
The question deals with the application of Charles's Law of gases, which states that at constant pressure, the volume of a gas is directly proportional to its absolute temperature (measured in Kelvin). To find the volume of air exiting the evaporator after cooling from 90°F/32°C to 70°F/21°C, we will use this principle.
Charles's Law is described by the formula V1/T1 = V2/T2. First, we convert the Celsius temperatures to Kelvin by adding 273.15 to each. So our temperatures become: T1 = 32°C + 273.15 = 305.15 K and T2 = 21°C + 273.15 = 294.15 K. Using the initial volume of V1 = 2500 ft3 and T1, we solve for the unknown V2 at the new temperature T2.
The equation becomes (2500 ft3 / 305.15 K) = V2 / 294.15 K. Solving for V2, we find the new volume of air exiting the evaporator coil. Because the temperature decreases, we expect the volume will also decrease according to Charles's Law.