101k views
4 votes
A fishing fleet delivers fresh fish to a cannery factory, where the fish is canned. Suppose that daily input to the cannery follows the following pattern: (1) 100 tons/hr. between 8 a.m. and 12 noon, (2) 75 tons/hr. between 1 p.m. and 3 p.m., and (3) 100 tons/hr. between 3 p.m. and 5 p.m. Note that there is no input between 12 noon and 1 p.m. The processing capacity of the cannery is: (1) 100 tons/hr. between 8 a.m. and 11 a.m., (2) 50 tons/hr. between 11 a.m. and 2 p.m., and (3) 100 tons/hr. between 2 p.m. and 5 p.m. Assume that there is unlimited freezer space for unprocessed fish.

a. Draw an inventory buildup diagram that shows inventory of unprocessed fish in the freezer starting at 8 a.m. and ending at 5 p.m.
b. Consider a fish that enters the cannery between 8 a.m. and 12 at noon. What is the average time (in minutes) spent by such a fish in the freezer before being packed?

User Rahul Raj
by
8.0k points

1 Answer

6 votes

Final answer:

a. The inventory buildup diagram shows the inventory of unprocessed fish in the freezer from 8 a.m. to 5 p.m. b. The average time spent by a fish in the freezer before being packed is 100 minutes.

Step-by-step explanation:

a. To draw an inventory buildup diagram, we need to calculate the net input and output of fish at each hour for the time period from 8 a.m. to 5 p.m. We can then plot these values on a graph to visualize the inventory buildup. Here is the calculation:

From 8 a.m. to 12 noon, the net input is 100 tons/hr. From 8 a.m. to 11 a.m., the net output is 100 tons/hr. Therefore, the inventory buildup is 100 tons/hr.

From 12 p.m. to 1 p.m., there is no input or output. Therefore, the inventory buildup remains the same.

From 1 p.m. to 3 p.m., the net input is 75 tons/hr. From 1 p.m. to 2 p.m., the net output is 50 tons/hr. Therefore, the inventory buildup is 75-50 = 25 tons/hr.

From 3 p.m. to 5 p.m., the net input is 100 tons/hr. From 3 p.m. to 5 p.m., the net output is 100 tons/hr. Therefore, the inventory buildup is 0 tons/hr.

b. A fish that enters the cannery between 8 a.m. and 12 noon will spend an average time in the freezer of (Inventory buildup) / (Net input per hour) minutes. From the inventory buildup diagram, we know that the inventory buildup during this time period is 100 tons/hr.

The net input per hour is also 100 tons/hr. Therefore, the average time spent by a fish in the freezer before being packed is 100 minutes.

User Chidinma
by
8.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories