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a vessel contains 2.50 mol of cf4, 4.00 mol of ch4, and 1.50 mol of kr gases. if the partial pressure of cf4 is 1.440 atm, what is the total pressure inside the vessel?

User Allolex
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Final Answer:

The total pressure inside the vessel can be calculated using Dalton's law of partial pressures. Adding the partial pressures of each gas (CF₄, CH₄, and Kr) together, the total pressure inside the vessel is 7.44 atm.

Step-by-step explanation:

Dalton's law of partial pressures states that in a mixture of non-reacting gases, the total pressure exerted is the sum of the partial pressures of individual gases. Given the partial pressure of CF₄ as 1.440 atm, and knowing that the total moles of gas inside the vessel is 2.50 mol (CF₄) + 4.00 mol (CH₄) + 1.50 mol (Kr) = 8.00 mol, we can use the mole fraction to determine the partial pressures of CH₄ and Kr.

The mole fraction of CF₄ is 2.50 mol / 8.00 mol = 0.3125. Using this, we can find the partial pressure of CH₄ and Kr. The partial pressure of CH₄ is 0.3125 (total pressure) - 1.440 atm (partial pressure of CF₄) = 6.00 atm. Similarly, the partial pressure of Kr is 7.44 atm (total pressure) - 1.440 atm (partial pressure of CF₄) = 5.00 atm.

Adding these partial pressures together: 1.440 atm (CF₄) + 6.00 atm (CH₄) + 5.00 atm (Kr) = 7.44 atm, which represents the total pressure inside the vessel according to Dalton's law. Thus, the total pressure inside the vessel, considering the contributions of each gas, is 7.44 atm.

User Pstryk
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