Final answer:
Cam can maximize the meditation space by creating a rectangle with dimensions 23 meters in length and 11.5 meters in width, using the available 46 meters of fencing to enclose the space on three sides.
Step-by-step explanation:
The student is tasked with determining the dimensions that maximize the area of a rectangular meditation space using a fixed amount of fencing.
In this case, Cam has 46 meters of fencing and needs to enclose a space with three sides, which means the fourth side is already existing, for example, a wall. If we denote the length of the rectangle by L and the width by W, and since only three sides need fencing, the perimeter P that Cam can use is 2W + L = 46 meters.
To maximize the area A of the rectangle, which is A = L * W, we can express L as L = 46 - 2W and substitute this into the area formula to get A = W * (46 - 2W). To find the maximum area, we set the derivative of A with respect to W to zero, A' = 46 - 4W = 0. Solving for W, we get W = 11.5 meters.
Substituting back into the perimeter equation, we find the length L = 46 - 2(11.5) = 23 meters. Therefore, the dimensions that give the maximum area are a length of 23 meters and a width of 11.5 meters.