Question

A ball is thrown from a height of 65 meters with an initial downward velocity of 10/ms. The ball's height h (in meters) after t seconds is given by the following.

Answer 1

H=79-6t-5t^2

Explanation:

The ball's height h (in meters) after t seconds is given by the following equation: h=79-6t-5t^2123. To find out how long after the ball is thrown it hits the ground, we need to find the value of t when h=0. This is because the ball hits the ground when its height is zero. To solve for t, we need to solve the quadratic equation 5t^2+6t-79=0. The solutions to this equation are t=3.15 seconds and t=-5.05 seconds. Since time cannot be negative, the ball hits the ground after approximately 3.15 seconds3.