Final answer:
The minimum thickness for the non-reflective coating on glass with a refractive index of 1.50 for light with a wavelength of 600 nm is approximately 115.38 nm.
Step-by-step explanation:
The question deals with calculating the minimum thickness of a non-reflective coating using the principles of thin film interference in optics. For destructive interference to occur, which minimizes reflection, the film's thickness (t) should be such that the optical path difference between the light reflected from the top surface and the one reflected from the interface with the glass results in a half-wavelength shift (a path difference of λ/2n, where λ is the wavelength in the vacuum and n is the refractive index of the coating). According to this criterion, the minimum thickness (t) for a non-reflective coating can be calculated using the formula: t = λ/(4n). Considering the light of wavelength 600 nm and a transparent material with an index of refraction of 1.30, we can proceed with the calculation.
Using the formula provided: t = 600 nm / (4 * 1.30) = 600 nm / 5.20 = 115.38 nm. Thus, the minimum thickness required for the transparent material coating on a surface of glass to be non-reflective for 600 nm light is approximately 115.38 nm.