Question

An electron with a speed of 5.0 x 10^5 m/s enters through a hole in a positively charged plate and collides with the negative plate at a speed of 1.0 x 10^5 m/s. what is the potential difference between the plates?

Answer 1

The potential difference between the plates is approximately
`6.3 x 10^-14 V.`

Step-by-step explanation:

The potential difference between the plates can be calculated using the formula:

V = (1/2)mvfinal2 - (1/2)mvinitial2 / q

where V is the potential difference, m is the mass of the electron, vfinal is the final velocity of the electron, vinitial is the initial velocity of the electron, and q is the charge of the electron.

In this case, the initial velocity of the electron is 5.0 x 10^5 m/s, the final velocity is 1.0 x 10^5 m/s, the mass of the electron is 9.11 x 10^-31 kg, and the charge of the electron is -1.6 x 10^-19 C.

Plugging these values into the formula, we get:

V = (1/2)(9.11 x 10^-31 kg)(1.0 x 10^5 m/s)^2 - (1/2)(9.11 x 10^-31 kg)(5.0 x 10^5 m/s)^2 / (-1.6 x 10^-19 C)

Calculating this expression gives a potential difference of -6.3 x 10^-14 V. Since potential difference is a scalar quantity, we can discard the negative sign and the final potential difference is 6.3 x 10^-14 V.

Therefore, the potential difference between the plates is approximately 6.3 x 10^-14 V.