Question

Determine the potential of a concentration cell that is constructed with solutions of pb(no3)2 at 0.20 m and 5.0 x 10^-4 m

a. 0.084 v
b. 0.077 v
c. 0.075 v
d. 0.080 v

Answer 1

To determine the potential of a concentration cell, use the Nernst equation with the given concentrations. The potential is approximately 0.084 V. The option (A) is correct.

Step-by-step explanation:

A concentration cell is a type of electrochemical cell that has the same components in both compartments, but different concentrations. To determine the potential of a concentration cell, you can use the Nernst equation:

Ecell = E°cell - (RT/nF) x ln([Pb²+]1 / [Pb²+]2)

Given that the concentrations are [Pb(NO3)2] = 0.20 M and [Pb(NO3)2] = 5.0 x 10-4 M, and the standard potential for the reaction Pb²+ + 2e¯ → Pb is -0.13 V, you can calculate the potential:

Ecell = -0.13 V - (0.059 V/n) x log10(0.20/5.0 x 10-4) ≈ 0.084 V. Therefore, option (A) is correct.