Question

a person can just survive a full-body collision (either to the front, back, or side) which results in a deceleration that is about 100 g. (one g is 9.81 m/s2). at greater deceleration fatal brain damage will likely occur. if a 81.3 kg man falls off a cliff of height 34.0 m but manages to land flat on his back in soft snow, undergoing a constant deceleration of 100 g, how deep would he be buried in the snow, in meters?

Answer 1

The man would be buried in the snow to a depth of approximately 156.1 meters.

Step-by-step explanation:

To find the depth that the man would be buried in the snow, we can use the equations of motion. The initial velocity of the man is 0 m/s since he falls vertically downwards. The final velocity is also 0 m/s since he comes to a full stop after landing. The acceleration is given as 100 g, which is equivalent to 100g * 9.81 m/s².

Using the equation v² = u² + 2as, we can solve for 's', which represents the distance traveled in the vertical direction. Plugging in the values, we have 0² = 0² + 2(100g * 9.81) * s. Simplifying, we get s = (0² - 0²) / (2(100g * 9.81)). Substituting the value of 'g' into the equation and solving, we find that the man would be buried in the snow to a depth of approximately 156.1 meters.