Question

What is the number of moles of

NaOH
NaOH used in the titration to reach the equivalence point, given that the standardized
NaOH
NaOH solution has a concentration of [insert concentration here] (to 4 or 5 significant figures)?
a) The number of moles cannot be determined without additional information.
b) The number of moles is equal to the concentration of
NaOH
NaOH multiplied by the volume used in the titration.
c) The number of moles is inversely proportional to the concentration of
NaOH
NaOH and directly proportional to the volume used in the titration.
d) The number of moles is equal to the volume used in the titration divided by the concentration of
NaOH
NaOH.

Answer 1

The number of moles of NaOH in a titration to reach the equivalence point can be calculated by multiplying the concentration of NaOH (M) by the volume used (L), considering a one-to-one mole ratio in the neutralization reaction with the acid.

Step-by-step explanation:

The number of moles of NaOH used in the titration to reach the equivalence point can be calculated using the concentration of the NaOH solution and the volume of NaOH solution used in the titration. Assuming we have the concentration in molarity (M), which represents moles per liter, and the volume of the solution in liters, the calculation is straightforward:

Number of moles of NaOH = Concentration of NaOH (M) × Volume of NaOH solution used (L)

For example, if the concentration of the NaOH solution is 0.100 M and the volume used in the titration is 12.6 mL, or 0.0126 L, then:

Number of moles of NaOH = 0.100 M × 0.0126 L = 0.00126 mol NaOH

This calculation relies on the balanced chemical equation, which shows a one-to-one mole ratio between the acid (HCl) and the base (NaOH) in the neutralization reaction HCl (aq) + NaOH (aq) → NaCl (aq) + H₂O.