Final answer:
To find the Bragg's angle for the first order diffraction of the (111) plane in a thin Cu film using the given electron wavelength and lattice parameter, we utilize the Bragg's Equation and a geometric relationship involving the camera length and the diffraction spot distance on the photographic plate.
Step-by-step explanation:
The Bragg's angle is the angle at which constructive interference occurs due to electron diffraction in a crystal lattice, resulting in a diffraction pattern. According to the Bragg's condition, this occurs when the path length difference (PLD) between the waves reflected from successive crystal planes is a whole number of wavelengths. The Bragg Equation which expresses this condition is nλ = 2d sin θ, where n is the order of the diffraction, λ is the wavelength of the electrons, d is the spacing between planes in the crystal, and θ is the Bragg's angle. Given an electron wavelength of 3.40x10^-12 m, a lattice parameter (d-spacing) of 3.1600x10^-10 m, and using the small angle approximation, we can calculate the Bragg's angle for the first order diffraction of the (111) plane in a thin Cu film.
Using a geometrical relation involving the camera length (L) and the distance (r) between the transmitted and diffracted spots on the photographic plate, we can express sin θ as r / (2L), where L is the distance between the sample and the photographic plate. Thus, by manipulating the Bragg Equation and substituting known values, we can solve for the Bragg's angle θ.