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you react 1.1 ml of ethanol with 7 drops of sulfuric acid and 5.202 g of salicylic acid, what is the % yield of the reaction if you synthesized 0.930 g of pure ethyl salicylate? the molecular weight of salicylic acid is 138.12 g/mol, the molecular weight of ethyl salicylate is 166.17 g/mol. the molecular weight of ethanol is 46.069 g/mol and its density is 0.789 g/ml. the molarity of sulfuric acid is 18 mol/l your answer:m/homework-help/questions-and-answers/question-4-1-point-e-react-64-ml-acetic-anhydride-7-drops-sulfuric-acid-3479-g-salicylic-a-q25328735

User Alex Peta
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Final answer:

To calculate the % yield of the reaction, determine the theoretical yield of ethyl salicylate and calculate the ratio of the actual yield to the theoretical yield.

Step-by-step explanation:

To calculate the % yield of the reaction, we first need to determine the theoretical yield, which is the amount of ethyl salicylate that would be produced if the reaction went to completion.

The balanced chemical equation for the reaction is:

C₇H₆O₃ + C₂H₅OH → C₁₀H₁₀O₄ + H₂O

From the equation, we can see that the mole ratio between salicylic acid and ethyl salicylate is 1:1.

The molar mass of salicylic acid is 138.12 g/mol, so the number of moles of salicylic acid used in the reaction is:

(5.202 g)/(138.12 g/mol) = 0.0377 mol

Since the mole ratio is 1:1, the theoretical yield of ethyl salicylate is also 0.0377 mol.

The molar mass of ethyl salicylate is 166.17 g/mol, so the theoretical yield in grams is:

(0.0377 mol) * (166.17 g/mol) = 6.264 g

Therefore, the theoretical yield is 6.264 g.

To calculate the % yield, we divide the actual yield (0.930 g) by the theoretical yield (6.264 g) and multiply by 100:

(0.930 g / 6.264 g) * 100 = 14.8%

The % yield of the reaction is 14.8%.

User Hellblazer
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