Final answer:
The electric field intensity between two flat metal plates with a separation of 2.0 cm and a potential difference of 150 volts is calculated using the formula E = V/d, resulting in an electric field intensity of 7500 V/m.
Step-by-step explanation:
To find the electric field intensity between two flat metal plates that are separated by a distance and have a potential difference applied between them, you can use the formula:
E = V/d
Where E is the electric field intensity (V/m), V is the potential difference (volts), and d is the separation distance (meters).
In this problem, the potential difference V is 150 volts, and the separation distance d is 2.0 cm (which should be converted to meters, thus 0.02 meters).
Now we can calculate the electric field intensity:
E = 150 V / 0.02 m = 7500 V/m
Therefore, the electric field intensity between the plates is 7500 V/m.