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A charge of 0.67 c is placed in an electric field of intensity 3.8 x 10^3 n/c. determine the acceleration of the charge if its mass is 1.84 x 10^-24 kg.

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Final answer:

The acceleration of the charge is 1.385 x 10²⁴ m/s².

Step-by-step explanation:

To determine the acceleration of the charge, we can use Newton's second law, which states that the force on an object is equal to its mass times its acceleration (F = ma).

Given: charge (q) = 0.67 C, electric field intensity (E) = 3.8 x 10³ N/C, and mass (m) = 1.84 x 10⁻²⁴ kg.

First, we need to find the force (F) using the equation F = qE.

Substituting the given values, we have F = (0.67 C)(3.8 x 10³ N/C) = 2.546 N.

Next, we can rearrange the equation F = ma to solve for acceleration (a). Substituting the values, we have 2.546 N = (1.84 x 10⁻²⁴ kg)a.

Solving for a, we get a = 2.546 N / (1.84 x 10⁻²⁴ kg) = 1.385 x 10²⁴ m/s².

Therefore, the acceleration of the charge is 1.385 x 10²⁴ m/s².

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