Final answer:
To show that 2n², you can use a combinatorial argument by taking terms from the series and adding them together step by step.
Step-by-step explanation:
To provide a combinatorial argument to show that if n is a positive integer, then 2n², imagine taking (n − 1) from the last term and adding it to the first term = 2[1+(n−1)+3 +...+(2n − 3 )+(2n − 1)−(n − 1)].
Now take (n − 3) from the penultimate term and add it to the second term 2[n +n + ... +n + n] = 2n².