Final Answers:
(a) Joint probability mass function of Z and W:
![\[ P(Z = z, W = w) = \begin{cases} \frac{{\binom{4}{z} \cdot \binom{48}{w-z}}}{{\binom{52}{w}}} & \text{if } 0 \leq z \leq w \leq 4 \\ 0 & \text{otherwise} \end{cases} \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/e9pohjy9njog7di7nsg0dwz0du3y639vdo.png)
(b) Marginal probability mass function of Z:
![\[ P(Z = z) = \sum_(w=z)^(4) P(Z = z, W = w) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/dis7clum20gswjiypckzeeyl4ekumifm9r.png)
(c) Conditional probability mass function of W given Z = 1:
![\[ P(W = w | Z = 1) = \begin{cases} \frac{{\binom{3}{w-1} \cdot \binom{48}{1}}}{{\binom{51}{w}}} & \text{if } 1 \leq w \leq 4 \\ 0 & \text{otherwise} \end{cases} \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/ec8dcerphh7g0rac0tkdiunh0416dtn3um.png)
Explanation:
The joint probability mass function of Z and W represents the probability of getting z aces in the first draw (Z) and a total of w aces in both draws (W). This is calculated by considering the combinations of aces and non-aces in the deck. The probability is the ratio of favorable outcomes to the total possible outcomes, which is
and 0 otherwise.
The marginal probability mass function of Z is the probability distribution of Z alone, disregarding the specific values of W. It is obtained by summing the joint probabilities over all possible values of W, ranging from z to 4. This is expressed as

The conditional probability mass function of W given Z = 1 focuses on the probability distribution of W given that Z is equal to 1. It calculates the probability of obtaining w aces in both draws when one ace is already drawn in the first attempt. This probability is
and 0 otherwise, determined by the combinations of aces and non-aces in the remaining deck after drawing one ace.
These functions allow for a comprehensive understanding of the probabilities associated with drawing aces in a two-card draw scenario from a standard deck of 52 cards.