Final answer:
The center of mass for the sticks on the x-axis is 0.85 m, and for the y-axis, it is 0.28 m. The calculation is made using the weighted average position of all the masses involved. Therefore, the correct answers are: (a) 0.85 m and (b) 0.28 m.
Step-by-step explanation:
The problem at hand is a classic Physics question that involves calculating the center of mass of a system. To find the center of mass along the x-axis for the three identical sticks, we need to use the formula for the center of mass of a system, which is the weighted average position of all the masses involved.
For the x-coordinate of the center of mass (xcm):
xcm = (m1x1 + m2x2 + m3x3) / (m1 + m2 + m3)
Since the sticks are identical and evenly placed, we can simplify:
xcm = (3.4 kg * 0.85 m + 3.4 kg * 1.7 m) / (3 * 3.4 kg)
xcm = (2.89 + 5.78) / 10.2
xcm = 0.85 m
For the y-coordinate of the center of mass (ycm), since only one stick contributes to the y-position:
ycm = (m1y1 + m2y2 + m3y3) / (m1 + m2 + m3)
ycm = (3.4 kg * 0.85 m) / (3 * 3.4 kg)
ycm = 0.85 m / 3
ycm = 0.28 m
Therefore, the correct answers are: (a) 0.85 m and (b) 0.28 m.