Question

A mass 8.10 kg is gently placed on the end of a freely hanging spring. the mass then falls 0.43 m before it stops and begins to rise. what is the frequency of the oscillation?

Answer 1

The frequency of the oscillation can be determined using the formula f = 1 / T, where f is the frequency and T is the period. By calculating the period of oscillation using the given displacement and mass of the object, we can then calculate the frequency.

Step-by-step explanation:

The frequency of the oscillation can be determined using the formula:

f = 1 / T

Where f is the frequency and T is the period. In this case, we are given the displacement (0.43 m) and the mass of the object (8.10 kg).

Using the formula for the period of oscillation:

T = 2π sqrt(m/k)

Where k is the spring constant, we can calculate the period as:

T = 2π sqrt(m/k) = 2π sqrt(8.10 / 9.81) ≈ 2.86 s

Finally, we can substitute the period into the frequency formula to get:

f = 1 / T = 1 / 2.86 ≈ 0.35 Hz