Question

assume salts are encoded as a binary string (1s and 0s) exactly 32 bits long. how many different passwords are there if the first 8 to 12 characters are lower case numbers, and the remaining characters is a binary string of length 32 acting as a salt?

Answer 1

The number of different passwords generated using a binary string salt and a range of lowercase letters as the first 8-12 characters can be calculated by multiplying the number of possibilities for each part.

Step-by-step explanation:

In this question, we are asked to determine the number of different passwords that can be generated using a binary string of length 32 as a salt, with the condition that the first 8 to 12 characters are lowercase letters. To solve this, we can consider the number of possibilities for each part separately and then multiply them together.

For the first 8 to 12 characters, we have 26 lowercase letters to choose from (a-z). Since the length can vary between 8 and 12, we can calculate the total number of possibilities as:

(12-8+1) * 26 = 5 * 26 = 130

For the remaining 32 characters, we have a binary string, which means each position can be either 0 or 1. So the total number of possibilities is 2^32 = 4,294,967,296. Therefore, the total number of different passwords is:

130 * 4,294,967,296 = 558,545,052,480