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How many molecules of CO2 are contained in a 5.00L tank at 7.53atm and 485K?

A. 3.21 × 10²³
B. 6.42 × 10²³
C. 9.63 × 10²³
D. 1.28 × 10²⁴

User Esmin
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1 Answer

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Final answer:

The number of molecules of CO2 in a 5.00L tank at 7.53atm and 485K is approximately 5.58 x 10^22.

The correct answer is none of all.

Step-by-step explanation:

To calculate the number of molecules of CO2 in the 5.00L tank, we need to use the ideal gas law equation: PV = nRT. In this equation, P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. First, we need to convert the pressure from atm to Pa, using the conversion factor 1 atm = 101325 Pa. Next, we convert the volume from L to m3, using the conversion factor 1 L = 0.001 m3. Finally, we solve the equation for n, the number of moles.

P = 7.53 atm x 101325 Pa/atm = 762106.25 Pa

V = 5.00 L x 0.001 m3/L = 0.005 m3

T = 485 K

R = 8.314 J/(mol K)

n = (PV) / (RT) = (762106.25 x 0.005) / (8.314 x 485)

n = 0.09277 mol of CO2

To convert the number of moles to molecules, we use Avogadro's number, which is 6.02 x 1023 mol-1.

Number of molecules = 0.09277 mol x 6.02 x 1023 mol-1 = 5.58 x 1022 molecules of CO2

User Qznc
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