Final answer:
The dehydrohalogenation of 2-bromobutane can form three different E2 products.
Step-by-step explanation:
When 2-bromobutane undergoes dehydrohalogenation, it can form three different E2 products. This reaction involves the removal of a hydrogen atom from the beta carbon (adjacent to the carbon bonded to the bromine) and the elimination of a bromine atom. The three possible products are:
- 1-butene, where the double bond is between the 1st and 2nd carbon atoms
- trans-2-butene, where the double bond is between the 2nd and 3rd carbon atoms
- cis-2-butene, where the double bond is also between the 2nd and 3rd carbon atoms, but the two substituents attached to the double bond are on the same side
Therefore, the correct answer is C) Three.