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Consider the generic reaction 2A(g) + B(g) → 2C(g)

a) Identify the reactants
b) Determine the rate law
c) Balance the equation
d) Calculate the reaction enthalpy

1 Answer

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Final answer:

The reactants in the provided reaction are 2A(g) and B(g). The rate law, assuming an elementary reaction, is second-order overall and would be Rate = k[A]^2[B]. The reaction is already balanced, and without specific enthalpy data, the reaction enthalpy (ΔH) cannot be calculated.

Step-by-step explanation:

The generic form of a chemical reaction is typically written as reactants yielding products. For example, reactants 2A(g) and B(g) yield product 2C(g) in the reaction provided. The reactants in this reaction are 2A(g) and B(g).

For the given reaction 2A(g) + B(g) → 2C(g), the rate law can be determined by knowing the orders of the reaction with respect to its reactants. Since no specific reaction mechanism is provided, we cannot determine the exact rate law, but for a hypothetical elementary reaction where the reaction order matches the stoichiometric coefficients, the rate law would be first-order in 2A and first order in B, making it second-order overall. Therefore, the rate law could be written as Rate = k[A]^2[B], assuming it is an elementary reaction.

The given reaction is already balanced with the correct stoichiometric coefficients. Lastly, to calculate the reaction enthalpy (ΔH), you would need the enthalpies of formation or bond energies for all reactants and products. Since this data is not provided in the question, we are unable to calculate the reaction enthalpy.

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