Final answer:
The concentration of lithium ions in a 0.360 M Li₃PO₄ solution is three times the concentration of Li₃PO₄, which would be 1.080 M. Given options do not include the correct answer, which suggests there may be an error in the question or the options provided.
Step-by-step explanation:
The question asks about the concentration of lithium ions in a 0.360 M Li₃PO₄ solution. To determine the concentration of the lithium ions, we must consider the stoichiometry of the dissociation of Li₃PO₄ in water. When one mole of Li₃PO₄ dissolves, it releases three moles of Li⁺ ions into the solution. Therefore, the concentration of lithium ions will be three times the concentration of the Li₃PO₄ solution.
To calculate this, we multiply the molarity of the Li₃PO₄ solution (0.360 M) by the number of moles of lithium ions per mole of Li₃PO₄ (3):
Concentration of Li⁺ = 0.360 M × 3 = 1.080 M
However, since the choices given are 0.360 M, 0.120 M, 0.240 M, and 0.480 M, it appears there is an error in the question or the options provided. Based on the calculation, the correct answer should be 'e) 1.080 M', but this option is not available in the choices. It's important to carefully review the options or possibly consult the source of the question to ensure there are no typos or misunderstandings.