Final answer:
The volume of a 0.724 M NaI solution that contains 0.405 mol of NaI is found by dividing the moles by molarity, giving us a volume of 0.560 L.
Step-by-step explanation:
The question asks to calculate the volume of a 0.724 M NaI solution that contains 0.405 mol of NaI.
The volume V can be calculated using the formula:
V = n / M
where n is the number of moles and M is the molarity of the solution.
Substituting the given values into the formula:
V = 0.405 mol / 0.724 M = 0.560 L
The correct answer is (a) 0.560 L, which is the volume that contains 0.405 mol of NaI in a 0.724 M solution.