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What volume in L of a 0.724 M NaI solution contains 0.405 mol of NaI?

a) 0.560 L
b) 0.890 L
c) 1.340 L
d) 2.220 L

User Varuni N R
by
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1 Answer

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Final answer:

The volume of a 0.724 M NaI solution that contains 0.405 mol of NaI is found by dividing the moles by molarity, giving us a volume of 0.560 L.

Step-by-step explanation:

The question asks to calculate the volume of a 0.724 M NaI solution that contains 0.405 mol of NaI.

The volume V can be calculated using the formula:

V = n / M

where n is the number of moles and M is the molarity of the solution.

Substituting the given values into the formula:

V = 0.405 mol / 0.724 M = 0.560 L

The correct answer is (a) 0.560 L, which is the volume that contains 0.405 mol of NaI in a 0.724 M solution.

User Avijit Gupta
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