Final answer:
The concentration of nitrate in a 0.250 M solution of Mg(NO₃)₂ is 0.04888 M.
Step-by-step explanation:
The concentration of nitrate (NO₃-) in a 0.250 M solution of Mg(NO₃)₂ can be determined by recognizing that there are two nitrate ions for every one Mg(NO₃)₂ unit. Therefore, the concentration of nitrate is twice the concentration of Mg(NO₃)₂.
In this case, the concentration of Mg(NO₃)₂ is given as 0.02444 M. So, the concentration of nitrate is 2 * 0.02444 M, which is 0.04888 M.