Final answer:
To find the mass of CO that can react with 0.310 kg of Fe₂O₃, we converted the mass of Fe₂O₃ to moles, used the stoichiometry of the reaction, and then converted the moles of CO to grams, resulting in 163.35 g of CO, which is rounded to 160 g.
Step-by-step explanation:
To calculate the mass of CO that can react with 0.310 kg of Fe₂O₃, we first convert the mass given to moles using the molar mass of Fe₂O₃, which is 159.7 g/mol. Since 0.310 kg is equivalent to 310 g, we use the following conversion:
- (310 g Fe₂O₃) / (159.7 g/mol) = 1.941 mol Fe₂O₃
The balanced chemical reaction is:
We see that 1 mole of Fe₂O₃ reacts with 3 moles of CO. Using stoichiometry, we find that 1.941 mol Fe₂O₃ will react with 3 times as many moles of CO. Then, we convert moles of CO to grams:
- (1.941 mol Fe₂O₃) x (3 mol CO / 1 mol Fe₂O₃) x (28.01 g/mol CO) = 163.35 g CO
Thus, the mass of CO is 163.35 g, which we can round to three significant figures, giving us 163 g. Therefore, the correct answer is B. 160 g.