225k views
2 votes
How many moles of solute are present in .75 l of 89 m solution

User Badsyntax
by
7.9k points

1 Answer

5 votes

Final answer:

To find the number of moles of solute in a 0.75 L solution with a molarity of 89 M, multiply the volume by the molarity, yielding 66.75 moles of solute.

Step-by-step explanation:

To determine how many moles of solute are present in a given solution, you can use the molarity formula:

moles of solute = Molarity (mol/L) x Volume of solution (L)

Given that the molarity (M) of the solution is 89 M, which means 89 moles of solute per liter of solution, and you have a 0.75 L solution, the calculation is straightforward:

moles of solute = 89 mol/L x 0.75 L

moles of solute = 66.75 mol

Therefore, there are 66.75 moles of solute in 0.75 liters of an 89 M solution.

User HelloThere
by
7.8k points