Question

a golf ball of mass 45.9g is launched from a height of 8m above the ground at a speed of 20m/s. at the maximum height above the ground, the ball has a speed of 12m/s. what is the max height of the ball

Answer 1

To calculate the maximum height of a golf ball launched from a certain height with an initial and final speed, we can use the principle of conservation of energy. At the maximum height, the ball has only potential energy and no kinetic energy.

Step-by-step explanation:

To calculate the maximum height of a golf ball launched from a certain height with an initial and final speed, we can use the principle of conservation of energy. At the maximum height, the ball has only potential energy and no kinetic energy, so we can equate the initial kinetic energy to the potential energy at the maximum height.

Using the equation for potential energy, PE = mgh, where m is the mass of the ball, g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height. Rearranging the equation, we have h = PE / (mg), which gives us the maximum height of the ball. Plugging in the values, we get h = (0.0459 kg * 9.8 m/s^2 * 8 m) / (0.0459 kg * 9.8 m/s^2) = 8 m.