Question

a student starts with a 6.0 m stock solution of nacl. 1.7 ml of this stock solution is removed and diluted to 50.0 ml, then 4.8 ml of this new solution is removed and diluted to 100.0 ml. what is the final concentration (m) of na (aq) after the two step serial dilution?

Answer 1

To find the final concentration of NaCl after a two-step serial dilution, use the formula C1V1 = C2V2 at each step, ensuring result precision through significant figures.

Step-by-step explanation:

The question involves the dilution of a concentrated solution of NaCl, specifically a two-step serial dilution. To solve this, you can use the formula C1V1 = C2V2, where C represents concentration and V represents volume. The initial concentration of NaCl stock solution (C1) is 6.0 M, the volume of stock solution used in the first dilution (V1) is 1.7 mL, the final volume after the first dilution (V2) is 50.0 mL. Applying the formula for the first dilution, you obtain the concentration after the first dilution (C2).

Then, for the second dilution, you use the concentration obtained from the first dilution as your new C1, 4.8 mL for V1, and 100.0 mL for the new V2. After calculations, you obtain the final concentration of NaCl.

It's important to make sure your final answer has the correct number of significant figures based on the precision of the given numbers.