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a baseball pitcher with a mass of 80 kg is initiallystanding at rest on extremely slippery artificial then throws a baseball with a mass of 0.14 kgwith a horizontal velocity of 50 m/s. determine therecoil velocity of the pitcher. reddit

User GLP
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Final answer:

The recoil velocity of the pitcher is 0.0875 m/s.

Step-by-step explanation:

To determine the recoil velocity of the pitcher, we can use the principle of conservation of momentum. The initial momentum of the system (pitcher + ball) is zero, since the pitcher is initially at rest. The final momentum of the system can be found using the equation p = m*v, where p is momentum, m is mass, and v is velocity.

Since the ball is thrown with a mass of 0.14 kg and a horizontal velocity of 50 m/s, its final momentum is (0.14 kg)(50 m/s) = 7 kg·m/s. To find the final velocity of the pitcher, we can rearrange the equation p = m*v to solve for v. Since the mass of the pitcher is 80 kg, the final velocity of the pitcher is (7 kg·m/s) / 80 kg = 0.0875 m/s.

User Zifius
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