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sponsors of a local charity decided to attract wealthy patrons to its $500-a-plate dinner by allowing each patron to buy a set of 12 tickets for the gaming tables. the chance of winning a prize for each of the 12 play is 50-50. if you bought 12 tickets, what is the chance of winning 10 or more prizes?

User Pratik B
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Final answer:

To calculate the probability of winning 10 or more prizes from 12 tickets with 50-50 odds, we use the binomial probability formula and sum the probabilities for 10, 11, and 12 successes out of 12 trials.

Step-by-step explanation:

The question relates to the calculation of the probability of a specific outcome when buying a set of gaming table tickets in the context of a charity dinner. Specifically, it asks for the probability of winning 10 or more prizes given that each of the 12 tickets has a 50-50 chance of winning. This can be approached using binomial probability distribution, which can be calculated using the formula for binomial probability:

P(X = x) = C(n, x) * p^x * (1-p)^(n-x)

Where:

  • C(n, x) is the combination of n items taken x at a time.
  • p is the probability of success on a single trial.
  • n is the number of trials.
  • x is the number of successes that result in a win.

To find the probability of winning 10, 11, or 12 prizes (out of 12), we would add up the individual probabilities:

P(X ≥ 10) = P(10) + P(11) + P(12)

Each P(x) would need to be calculated with the binomial formula using x as 10, 11, and 12 respectively and n as 12 because there are a total of 12 tickets. The resulting sum of these probabilities would give us the chance of winning 10 or more prizes.

User Mles
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