Final answer:
The parent with orange eyes and white skin is homozygous recessive for orange eyes (xx), as orange eye color is a recessive trait on the X chromosome. The offspring's black eyes and green skin phenotype indicate the other parent's genotype for eye color is XY. In an X-linked cross with a white-eyed male (xY) and a heterozygous red-eyed female (Xx), the offspring ratio would be 1:1 for red-eyed and white-eyed males, and all females would have red eyes.
Step-by-step explanation:
In an X-linked cross, if all first-generation offspring have black eyes and green skin when one parent has orange eyes (recessive) and white skin, it implies that orange eyes are recessive traits linked to the X chromosome. The genotype of the parent with orange eyes and white skin must then be homozygous recessive for the eye color trait (xx) and also homozygous for the skin color if we assume that skin color follows a similar inheritance pattern. Considering that all offspring have black eyes and green skin, and if we abstract skin color, the other parent must be XY with black eyes, and the orange-eyed parent must be xx because eye color is expressed as a recessive trait on the X chromosome. The outcome of this cross, with the genotype xx from the orange-eyed parent and XY from the black-eyed parent, would result in all offspring being carriers of the orange eye allele but displaying the dominant black eye phenotype.
For instance, if a white-eyed male (genotype xY) is crossed with a heterozygous red-eyed female (genotype Xx), the resulting offspring would be expected to have a 1:1 ratio of red-eyed to white-eyed males, and all red-eyed females due to the X-linked inheritance pattern.