Final answer:
Using rotational kinematics formulas, the angular velocity, swept angle, and tangential acceleration of a constantly accelerating disk can be calculated using the initial conditions and the time elapsed.
Step-by-step explanation:
Angular Acceleration and Kinematics of Rotational Motion
For a disk with constant angular acceleration, you can use the rotational kinematics formulas to solve for various quantities. Given a constant angular acceleration (α), the angular velocity (ω) at any time (t) can be found using the equation ω = ω0 + αt, where ω0 is the initial angular velocity. The angle (θ) swept by the disk in time t, given a constant angular acceleration, is found using θ = ω0t + (1/2)αt². In addition, the tangential acceleration (at) of a point on the edge of the disk is the product of the angular acceleration and the radius (r) of the disk, at = αr.
For example, a disk with an initial angular velocity of 2.0 rad/s and an angular acceleration of 1.0 rad/s² will have an angular velocity of 7.0 rad/s after 5 seconds and will have swept an angle of 22.5 radians (360° is approximately 6.28 radians) during that time. The tangential acceleration at the edge of the disk will be 10 m/s² if radius is 10 cm (0.1 m).