233k views
1 vote
13.93 ml of a solution of a monoprotic strong acid of unknown concentration requires 10.18 ml of a solution of 0.125 m naoh to reach the endpoint. what is the concentration of the strong acid solution in mol/l? report your answer to 3 decimal places and only report the numerical value (no units). do not use scientific notation to answer this question.

1 Answer

5 votes

Final answer:

The concentration of acid = (0.0012725 mol) / (0.01393 L) = 0.09137 M. To determine the concentration of the strong acid solution, we can use the number of moles of NaOH used at the endpoint. By calculating the moles of NaOH used, we can find the concentration of the strong acid solution.

Step-by-step explanation:

In a titration of a strong acid with a strong base, the number of moles of acid used is equal to the number of moles of base used at the endpoint. Thus, the moles of NaOH used can be used to determine the concentration of the strong acid solution.

Given that 13.93 mL of the strong acid solution requires 10.18 mL of a 0.125 M NaOH solution, we can calculate the moles of NaOH used:

Moles of NaOH = (0.125 M) * (0.01018 L) = 0.0012725 mol

Since the moles of acid used are equal to the moles of NaOH, the concentration of the strong acid solution is:

The concentration of acid = (0.0012725 mol) / (0.01393 L) = 0.09137 M

User Kartal Tabak
by
8.3k points