Final Answer:
If the distance 's' between two particles with positive charges q1 and q2 is doubled, the force between them decreases to one-fourth of the original force.
Step-by-step explanation:
The force between two charged particles is governed by Coulomb's Law, which states that the force is directly proportional to the product of the charges (q1 and q2) and inversely proportional to the square of the distance between them (s).
Mathematically, the formula is expressed as F = k * (q1 * q2) / s^2, where 'k' is Coulomb's constant.
When the distance 's' is doubled, the denominator in the equation becomes (2s)^2, resulting in a fourfold increase.
As a consequence, the force between the charges decreases to one-fourth of its original magnitude.
This relationship illustrates the sensitivity of electrostatic forces to changes in distance.
In practical terms, doubling the separation between the charged particles leads to a significant reduction in the force they exert on each other.
This phenomenon is crucial in understanding how charged entities interact over varying distances, providing insights into the dynamics of electric fields and the principles governing electrostatic interactions.
In summary, if the distance 's' between two positively charged particles is doubled, the force between them decreases to one-fourth of the original force.