Question

The probability that a selection contains only 3 flavors out of 7 available flavors is:

a) 1/21
b) 3/7
c) 1/7
d) 3/21

Answer 1

The probability that a selection contains only 3 flavors out of 7 available flavors is 3/21. Option d is the correct answer.

Step-by-step explanation:

To find the probability that a selection contains only 3 flavors out of 7 available flavors, we can use the concept of combinations.

Since there are 7 flavors available and we want to select only 3 flavors, the number of different combinations of 3 flavors out of 7 is given by C(7, 3) = 7! / (3! * (7-3)!), where ! denotes factorial.

Computing this, we get C(7, 3) = 35.

The total number of possible selections is the sum of all possible combinations, which is 2^7 = 128.

So, the probability of selecting only 3 flavors is 35/128.

Therefore, the correct option is d) 3/21.