Final answer:
Lead(II) sulfate is formed when sulfuric acid reacts with lead(II) acetate, resulting in a precipitation reaction due to the low solubility of lead(II) sulfate in water.
Step-by-step explanation:
When solutions of sulfuric acid and lead(II) acetate react together, they form lead(II) sulfate as a precipitate. Sulfuric acid is a diprotic acid and can form sulfates with metal cations. Lead(II) acetate dissolves in water to give Pb2+ and CH3CO2− ions. Because sulfates of lead are only slightly soluble in water, when these two solutions are mixed, lead(II) sulfate precipitates out of the solution.
The balanced chemical equation for this reaction is:
Pb(CH3CO2)2(aq) + H2SO4(aq) → PbSO4(s) + 2 CH3CO2H(aq)