Final answer:
The velocity of a ball dropped from rest in free fall after 3 seconds is 29.4 m/s, using the formula v = u + gt, where g represents the acceleration due to gravity.The velocity of the ball after falling for 3 seconds is 29.4 m/s, which corresponds to option A.
Step-by-step explanation:
The question pertains to the concept of free fall in physics. Here we assume the only force acting on the ball is gravity and that air resistance is negligible. The velocity of an object in free fall at any instance can be calculated using the acceleration due to gravity (g = 9.8 m/s²) and the time (t) it has been falling. The initial velocity (u) is given as 0 m/s. The formula utilized is given by v = u + gt, where v is the final velocity after time t.
Applying this formula to calculate the velocity of the ball after it has fallen for 3 seconds, the calculation would be:
- Initial velocity, u = 0 m/s
- Acceleration due to gravity, g = 9.8 m/s²
- Time, t = 3 s
Therefore, v = u + gt
v = 0 m/s + (9.8 m/s²)(3 s)
v = 0 m/s + 29.4 m/s
v = 29.4 m/s
The velocity of the ball after falling for 3 seconds is 29.4 m/s, which corresponds to option A.