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An antifreeze solution is made by mixing ethylene glycol (rho = 1116 kg/m³) with water.Suppose the specific gravity of such a solution is 1.0730. Assuming that the total volume of the solution is the sum of its parts, determine the volume percentage of ethylene glycol in the solution.

A) 9.5%
B) 12.7%
C) 14.0%
D) 17.3%

User Jtalarico
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1 Answer

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Final answer:

The volume percentage of ethylene glycol in the solution is 103.86%.

Step-by-step explanation:

To determine the volume percentage of ethylene glycol in the solution, we need to calculate the volume of ethylene glycol and water in the mixture. We will use the specific gravity of the solution to do this.

The specific gravity is the ratio of the density of the solution to the density of water. In this case, the specific gravity is given as 1.0730. We can calculate the density of the solution by multiplying the specific gravity by the density of water (1000 kg/m³).

Density of solution = Specific gravity x Density of water = 1.0730 x 1000 kg/m³ = 1073 kg/m³

The volume percentage of ethylene glycol can be calculated using the following formula:

Volume percentage of ethylene glycol = (Volume of ethylene glycol / Total volume of solution) x 100%

Let's assume that we have a 1 L solution. The volume of ethylene glycol can be calculated by:

Volume of ethylene glycol = (Density of ethylene glycol / Density of solution) x Volume of solution

Given that the density of ethylene glycol is 1116 kg/m³, the volume of ethylene glycol is:

Volume of ethylene glycol = (1116 kg/m³ / 1073 kg/m³) x 1 L = 1.0386 L

So, the volume percentage of ethylene glycol in the solution is:

Volume percentage of ethylene glycol = (1.0386 L / 1 L) x 100% = 103.86%

Therefore, the correct answer is not provided in the options. The volume percentage of ethylene glycol in the solution is 103.86% (rounded to two decimal places).

User Akber Choudhry
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