Final answer:
The wavelength λ of the wave described by the equation provided is found using the relation λ = 2π/k, where k is the wave number. In this case, k = 0.5, resulting in a wavelength λ = 2π/0.5, or option A.
Step-by-step explanation:
The student is asking how to find the wavelength λ of a transverse harmonic wave that is described by the equation y(x,t) = A sin(0.5 rad/s t - 0.5x + 6π/π). The general form of a wave equation is y(x, t) = A sin(kx - ωt + φ), where k is the wave number and λ is related to k by the equation λ = 2π/k. From the given wave equation, k = 0.5, so the wavelength λ = 2π/0.5, which is option A) 2π/0.5.