Question

At time t = 0, a projectile is launched from ground level. At t = 2.00 s, it is displaced d = 48 m horizontally and h = 52 m vertically above the launch point. What are the (a) horizontal

A) 24 m/s
B) 12 m/s
C) 36 m/s
D) 18 m/s

Answer 1

The horizontal velocity of the projectile is 24 m/s.

Step-by-step explanation:

Projectile motion can be analyzed independently in the horizontal and vertical directions. In this case, the projectile is launched at ground level and at t = 2.00s, it is displaced 48m horizontally and 52m vertically above the launch point. To find the horizontal velocity, we can divide the horizontal displacement by the time taken: horizontal velocity = horizontal displacement/time taken = 48m/2.00s = 24m/s.