Question

An electric field exerts a force of 2.6 N on a 3.4x10⁻⁸ C charge feels a force of 2.6 N. What is the magnitude of the electric field?

a. 7.65x10⁷N/C

b. 8.43x10⁷ N/C

c. 9.05x10⁷ N/C

d. 11.98x10⁷ N/C

Answer 1

The magnitude of the electric field can be calculated using the equation F = qE. Rearranging the equation, E = F/q. Substituting the values given (F = 2.6 N, q = 3.4x10⁻⁸ C), we find that the magnitude of the electric field is 7.65x10⁷ N/C.

Step-by-step explanation:

To find the magnitude of the electric field, we can use the equation F = qE, where F is the force, q is the charge, and E is the electric field strength. In this case, the force exerted on the charge is given as 2.6 N and the charge is 3.4x10⁻⁸ C. Rearranging the equation, we have E = F/q. Substituting the given values, we get E = 2.6 N / 3.4x10⁻⁸ C.

Calculating this gives the answer 7.65x10⁷ N/C, which is option a.