Question

A projectile is launched in the air from the ground with an initial velocity v₀ = 60 m/s. What is the maximum height that the projectile reaches?

A) 183.67 m
B) 120 m
C) 90 m
D) 45 m

Answer 1

Using the kinematic equation for vertical motion, the maximum height 'h' reached by the projectile is 183.67 m, so the correct answer is A) 183.67 m.

Step-by-step explanation:

To find the maximum height reached by a projectile launched from the ground with an initial vertical velocity (v₀), we use the kinematic equation for vertical motion:

0 = v₀2 + 2(a)(h), where 'a' is the acceleration due to gravity (which is -9.8 m/s2 because it is acting downward), and 'h' is the maximum height.

Rearranging the equation for 'h', we get:
h = -(v₀2)/(2a)

Using the given initial velocity v₀ = 60 m/s:

h = -(60 m/s)2 / (2 * -9.8 m/s2)

After simplifying, we find that the maximum height 'h' is:

h = 183.67 m

Therefore, the correct answer is A) 183.67 m.