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A hockey puck is hit on a frozen lake and starts moving with a speed of 15.0m/s. If it slowsdown at a rate of 1.3m/s² , what is the coefficient of kinetic friction between the ice and the puck?

A. 0.133
B. 0.167
C. 0.186
D. 0.214
E. 0.265

1 Answer

1 vote

Final answer:

To solve this problem, we can use Newton's second law of motion to calculate the force of kinetic friction and the coefficient of kinetic friction between the ice and the puck. The correct answer is option A: 0.133.

Step-by-step explanation:

To solve this problem, we can use Newton's second law of motion which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the net force is equal to the force of kinetic friction, which can be calculated as the product of the coefficient of kinetic friction and the normal force. The normal force is equal to the weight of the object, which can be calculated as the mass of the object multiplied by the acceleration due to gravity.

The acceleration of the puck can be calculated using the equation of motion:

v^2 = u^2 + 2aS

where v is the final velocity (0 m/s), u is the initial velocity (15.0 m/s), a is the acceleration (-1.3 m/s²), and S is the distance travelled.

Plugging in the given values, we can solve for S. Once we find the distance travelled, we can calculate the force of kinetic friction and the coefficient of kinetic friction using the equations mentioned earlier. The correct answer is option A: 0.133.

User Subin Babu
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