Final answer:
The incorrect statements regarding the galvanic cell made of silver and vanadium half-cells are that Ag (silver) is oxidized. Ag is actually reduced, and the calculation of the overall cell potential E°cell is correct.
Step-by-step explanation:
When considering the statements given about a galvanic cell made of silver and vanadium half-cells, there are a couple of inaccuracies. First, given that the silver half-cell has a standard reduction potential (E°) of 0.7993V, silver (Ag) is indeed reduced in the cell. Second, since the standard reduction potential of the vanadium half-cell is -1.125V, vanadium (V) is oxidized. The cell potential (E°cell) is correctly calculated as the difference in reduction potentials of the cathode and anode, which in this case would be E°cell = E°cathode - E°anode = 0.7993V - (-1.125V) = 1.9243V. This calculation is in line with the statement that E°cell = 1.924V. Lastly, since the Ag+ is reduced to Ag, it is not correct that Ag is oxidized. Therefore, statements that are not correct are: Ag is oxidized.