Question

Please help me with this questionnn :^​

Answer 1

To find the height of the skyscraper, we can use trigonometry and the concept of similar triangles.

First, let's label the given information:

The angle of elevation from Francisco's eye to the top of the skyscraper is 32°.

The distance between Francisco and the base of the skyscraper is 376 meters.

The height of Francisco's eye above the ground is 1.59 meters.

Now, let's set up a right triangle with the following measurements:

The vertical leg represents the height of the skyscraper.

The horizontal leg represents the distance between Francisco and the base of the skyscraper.

The angle between the horizontal leg and the line connecting Francisco's eye to the top of the skyscraper is 90° - 32° = 58°.

Next, we can use the tangent function to find the height of the skyscraper:

tan(58°) = height of the skyscraper / distance between Francisco and the base of the skyscraper

Rearranging the equation to solve for the height of the skyscraper:

height of the skyscraper = tan(58°) * distance between Francisco and the base of the skyscraper

Now, let's substitute the given values into the equation:

height of the skyscraper = tan(58°) * 376 meters

Using a scientific calculator, we find that tan(58°) is approximately 1.616.

Calculating the height of the skyscraper:

height of the skyscraper ≈ 1.616 * 376 meters

height of the skyscraper ≈ 607.616 meters

Therefore, the height of the skyscraper is approximately 607.6 meters when rounded to the nearest tenth of a meter.

Answer 2

The height of the sky scraper is 236.5 m (to the nearest tenth)

How to determine the height of the skyscraper

Information from the question

opposite = height of the skyscraper - 1.59 m = (H - 1.59)

adjacent = distance of the building = 376 m

Using SOH CAH TOA

Sin = opposite / hypotenuse - SOH

Cos = adjacent / hypotenuse - CAH

Tan = opposite / adjacent - TOA

tan 32 = (H - 1.59) / 376

(H - 1.59) = tan 32 * 376

(H - 1.59) = 234.951

H = 234.951 + 1.56

H = 236.51 m