Question

a sample of hi (9.30 x 10-3 mol) was placed in an empty 2.00 l container at 1000k. after equilibrium was reached, the concentration of i2 was 6.29 x 10-4 m. calculate the value of kc at 1000k for the reaction.

Answer 1

The value of Kc at 1000K for the given reaction is approximately 4.00 x 10^-5.

Step-by-step explanation:

To calculate the value of Kc at 1000K for the given reaction, we need to use the equation:

Kc = [HI]^2 / [H2] * [I2]

Given that the concentration of HI is 6.29 x 10^-4 M, and the concentration of H2 is 9.30 x 10^-3 M, we can substitute these values into the equation:

Kc = (6.29 x 10^-4)^2 / (9.30 x 10^-3) * (9.30 x 10^-3)

Simplifying the equation gives us:

Kc ≈ 4.00 x 10^-5