Question

curling is a sport played with 20 kg stones that slide across an ice surface. suppose a c url ing stone sliding at 1 mis strikes another, stationary stone and comes to rest in 2 ms. approximately how much force is there on the stone during the impact?

Answer 1

To calculate the force on a curling stone during an impact, use Newton's second law to find acceleration and then multiply by the stone's mass, resulting in a force of -10,000 N.

Step-by-step explanation:

The question deals with a curling stone and requires calculating the force exerted on the stone during impact. To find this force, one can use Newton's second law of motion, which relates force (F), mass (m), and acceleration (a): F = m × a. First, we find the acceleration by considering the change in velocity, which is 1 m/s to 0 m/s in the given time span of 2 ms or 0.002 seconds.

The acceleration a is then (0 m/s - 1 m/s) / 0.002 s = -500 m/s² (negative sign indicates deceleration). The force is calculated by multiplying the mass of 20 kg by this acceleration, resulting in F = 20 kg × (-500 m/s²) = -10,000 N. The negative sign here indicates that the force is in the opposite direction of the stone's initial movement.