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What is the mass of carbon present in 0.5 mole of sucrose?

a) 6 grams
b) 12 grams
c) 24 grams
d) 36 grams

User Jogshardik
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1 Answer

2 votes

Final answer:

The mass of carbon in 0.5 mole of sucrose is 72 grams, but this answer does not match the provided multiple-choice options, indicating a potential error in the question or options.

Step-by-step explanation:

The student asked what the mass of carbon present in 0.5 mole of sucrose is. Sucrose has a molecular formula of C12H22O11, meaning there are 12 carbon atoms in one mole of sucrose. One mole of carbon has a mass of 12.0 g, which means the mass of carbon present in one mole of sucrose is 12 atoms × 12.0 g/mol = 144 g/mol of carbon in sucrose. Therefore, for 0.5 mole of sucrose, the mass of carbon is 0.5 moles × 144 g/mol = 72 grams. However, this response does not match any of the options provided (a-d), suggesting a possible error in the question or the response options.

User Jvenezia
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